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5x^2-10=-23x
We move all terms to the left:
5x^2-10-(-23x)=0
We get rid of parentheses
5x^2+23x-10=0
a = 5; b = 23; c = -10;
Δ = b2-4ac
Δ = 232-4·5·(-10)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-27}{2*5}=\frac{-50}{10} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+27}{2*5}=\frac{4}{10} =2/5 $
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